ASVAB Math Knowledge Practice Test 403194

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4c + 5c = -2c - 7y - 1 for c in terms of y.

y - 6
1\(\frac{5}{6}\)y - \(\frac{1}{2}\)
-1\(\frac{2}{5}\)y - \(\frac{4}{5}\)
-2y - \(\frac{1}{6}\)