| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
If angle a = 32° and angle b = 48° what is the length of angle d?
| 121° | |
| 138° | |
| 148° | |
| 160° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 32° - 48° = 100°
So, d° = 48° + 100° = 148°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 32° = 148°
Find the value of c:
3c + y = -9
-2c - y = 4
| 3\(\frac{3}{5}\) | |
| -5 | |
| -1\(\frac{7}{9}\) | |
| -\(\frac{9}{19}\) |
You need to find the value of c so solve the first equation in terms of y:
3c + y = -9
y = -9 - 3c
then substitute the result (-9 - 3c) into the second equation:
-2c - 1(-9 - 3c) = 4
-2c + (-1 x -9) + (-1 x -3c) = 4
-2c + 9 + 3c = 4
-2c + 3c = 4 - 9
c = -5
c = \( \frac{-5}{1} \)
c = -5
If side x = 8cm, side y = 7cm, and side z = 14cm what is the perimeter of this triangle?
| 34cm | |
| 28cm | |
| 41cm | |
| 29cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 8cm + 7cm + 14cm = 29cm
A quadrilateral is a shape with __________ sides.
3 |
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2 |
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4 |
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5 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
Solve for z:
-5z + 3 = \( \frac{z}{-6} \)
| \(\frac{7}{11}\) | |
| -\(\frac{20}{29}\) | |
| \(\frac{18}{29}\) | |
| -\(\frac{5}{24}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-5z + 3 = \( \frac{z}{-6} \)
-6 x (-5z + 3) = z
(-6 x -5z) + (-6 x 3) = z
30z - 18 = z
30z - 18 - z = 0
30z - z = 18
29z = 18
z = \( \frac{18}{29} \)
z = \(\frac{18}{29}\)