ASVAB Math Knowledge Practice Test 403790

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c - 4c = 9c - 2y + 2 for c in terms of y.

-\(\frac{2}{3}\)y - \(\frac{2}{3}\)
y - \(\frac{1}{4}\)
\(\frac{1}{3}\)y + 1\(\frac{2}{3}\)
2\(\frac{1}{2}\)y - 1