When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2b + 5b = -2b + 3z + 6 for b in terms of z.
| -\(\frac{1}{3}\)z + \(\frac{5}{6}\) | |
| 3z + 5 | |
| -\(\frac{1}{2}\)z + 1\(\frac{1}{2}\) | |
| \(\frac{4}{5}\)z + \(\frac{1}{5}\) |