| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.66 |
| Score | 0% | 53% |
Solve for z:
-6z + 6 < -6 - 4z
| z < \(\frac{1}{8}\) | |
| z < 6 | |
| z < -\(\frac{1}{2}\) | |
| z < -5 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-6z + 6 < -6 - 4z
-6z < -6 - 4z - 6
-6z + 4z < -6 - 6
-2z < -12
z < \( \frac{-12}{-2} \)
z < 6
The endpoints of this line segment are at (-2, 9) and (2, -1). What is the slope-intercept equation for this line?
| y = -2x + 2 | |
| y = 1\(\frac{1}{2}\)x - 2 | |
| y = -2\(\frac{1}{2}\)x + 4 | |
| y = -x + 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 9) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (9.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)Plugging these values into the slope-intercept equation:
y = -2\(\frac{1}{2}\)x + 4
Which of the following statements about a parallelogram is not true?
the perimeter of a parallelogram is the sum of the lengths of all sides |
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a parallelogram is a quadrilateral |
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opposite sides and adjacent angles are equal |
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the area of a parallelogram is base x height |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
The dimensions of this cylinder are height (h) = 7 and radius (r) = 9. What is the surface area?
| 72π | |
| 176π | |
| 20π | |
| 288π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 7)
sa = 2π(81) + 2π(63)
sa = (2 x 81)π + (2 x 63)π
sa = 162π + 126π
sa = 288π
What is the area of a circle with a diameter of 8?
| 3π | |
| 64π | |
| 16π | |
| 9π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr2
a = π(42)
a = 16π