When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c - c = 3c + 4x - 3 for c in terms of x.
| -\(\frac{5}{9}\)x + \(\frac{1}{3}\) | |
| -\(\frac{2}{3}\)x + \(\frac{3}{4}\) | |
| \(\frac{1}{9}\)x - \(\frac{7}{9}\) | |
| \(\frac{2}{9}\)x + \(\frac{4}{9}\) |