When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 2c = 8c + 3z + 6 for c in terms of z.
| -\(\frac{5}{12}\)z - \(\frac{1}{2}\) | |
| 10z + 1 | |
| -1\(\frac{3}{8}\)z + \(\frac{1}{4}\) | |
| \(\frac{1}{2}\)z + \(\frac{1}{3}\) |