When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = -3c - 7y + 1 for c in terms of y.
| -1\(\frac{1}{11}\)y + \(\frac{1}{11}\) | |
| -1\(\frac{1}{4}\)y - \(\frac{3}{4}\) | |
| 16y + 1 | |
| 3\(\frac{1}{2}\)y + 2 |