When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 4c = 7c - y - 3 for c in terms of y.
| 2\(\frac{3}{4}\)y - 1\(\frac{3}{4}\) | |
| \(\frac{5}{16}\)y - \(\frac{1}{4}\) | |
| y + \(\frac{3}{5}\) | |
| -1\(\frac{1}{3}\)y + 1\(\frac{1}{3}\) |