ASVAB Math Knowledge Practice Test 411391 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

Simplify (4a)(6ab) - (4a2)(3b).

62% Answer Correctly
12a2b
-12ab2
70ab2
36ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(6ab) - (4a2)(3b)
(4 x 6)(a x a x b) - (4 x 3)(a2 x b)
(24)(a1+1 x b) - (12)(a2b)
24a2b - 12a2b
12a2b


2

If side a = 3, side b = 6, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{97} \)
\( \sqrt{45} \)
\( \sqrt{89} \)
\( \sqrt{50} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 32 + 62
c2 = 9 + 36
c2 = 45
c = \( \sqrt{45} \)


3

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
4\( \sqrt{2} \)
2\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)


4

The dimensions of this cylinder are height (h) = 3 and radius (r) = 2. What is the surface area?

48% Answer Correctly
90π
36π
20π
182π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 3)
sa = 2π(4) + 2π(6)
sa = (2 x 4)π + (2 x 6)π
sa = 8π + 12π
sa = 20π


5

What is the area of a circle with a diameter of 8?

69% Answer Correctly
36π
16π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{8}{2} \)
r = 4
a = πr2
a = π(42)
a = 16π