ASVAB Math Knowledge Practice Test 41182 Results

Your Results Global Average
Questions 5 5
Correct 0 2.83
Score 0% 57%

Review

1

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

trisects

bisects

intersects

midpoints


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

On this circle, line segment AB is the:

71% Answer Correctly

diameter

circumference

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Solve for x:
3x - 2 < 5 - x

55% Answer Correctly
x < -2\(\frac{2}{3}\)
x < 1\(\frac{3}{4}\)
x < 5
x < 1\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

3x - 2 < 5 - x
3x < 5 - x + 2
3x + x < 5 + 2
4x < 7
x < \( \frac{7}{4} \)
x < 1\(\frac{3}{4}\)


5

Simplify (9a)(3ab) + (4a2)(3b).

65% Answer Correctly
39a2b
84a2b
-15a2b
39ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(9a)(3ab) + (4a2)(3b)
(9 x 3)(a x a x b) + (4 x 3)(a2 x b)
(27)(a1+1 x b) + (12)(a2b)
27a2b + 12a2b
39a2b