ASVAB Math Knowledge Practice Test 414401

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4c - 3c = 3c + 4z + 8 for c in terms of z.

-z - 1\(\frac{1}{7}\)
1\(\frac{1}{7}\)z + \(\frac{3}{7}\)
\(\frac{1}{2}\)z + 1\(\frac{3}{4}\)
2\(\frac{1}{2}\)z + 1