When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 3c = 3c + 2x + 8 for c in terms of x.
| \(\frac{3}{5}\)x + \(\frac{1}{2}\) | |
| 1\(\frac{1}{4}\)x - \(\frac{1}{8}\) | |
| -3\(\frac{2}{3}\)x - 2 | |
| \(\frac{1}{8}\)x - 1 |