When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c - 3c = 3c + z - 3 for c in terms of z.
| 2z - \(\frac{1}{2}\) | |
| \(\frac{6}{11}\)z - \(\frac{2}{11}\) | |
| -\(\frac{4}{5}\)z + \(\frac{3}{5}\) | |
| -\(\frac{2}{11}\)z + \(\frac{6}{11}\) |