| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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normalizing |
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deconstructing |
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squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
If AD = 30 and BD = 28, AB = ?
| 20 | |
| 7 | |
| 2 | |
| 18 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD
The endpoints of this line segment are at (-2, 3) and (2, -7). What is the slope of this line?
| -2 | |
| -2\(\frac{1}{2}\) | |
| -\(\frac{1}{2}\) | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, -7) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-7.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-10}{4} \)Solve 7a + 6a = 2a - 2x - 4 for a in terms of x.
| -1\(\frac{3}{5}\)x - \(\frac{4}{5}\) | |
| 5\(\frac{1}{2}\)x - 2\(\frac{1}{2}\) | |
| 2\(\frac{3}{5}\)x - \(\frac{1}{5}\) | |
| \(\frac{7}{18}\)x + \(\frac{1}{18}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
7a + 6x = 2a - 2x - 4
7a = 2a - 2x - 4 - 6x
7a - 2a = -2x - 4 - 6x
5a = -8x - 4
a = \( \frac{-8x - 4}{5} \)
a = \( \frac{-8x}{5} \) + \( \frac{-4}{5} \)
a = -1\(\frac{3}{5}\)x - \(\frac{4}{5}\)
If a = 3, b = 4, c = 4, and d = 8, what is the perimeter of this quadrilateral?
| 19 | |
| 16 | |
| 21 | |
| 18 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 3 + 4 + 4 + 8
p = 19