When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3a + 5a = 2a + 8x + 1 for a in terms of x.
| 3x + 1 | |
| -\(\frac{1}{3}\)x + \(\frac{2}{3}\) | |
| \(\frac{1}{4}\)x - 1 | |
| 1\(\frac{1}{4}\)x - 1\(\frac{3}{4}\) |