When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - 5c = -6c + 9x + 9 for c in terms of x.
| -8\(\frac{1}{2}\)x + 3 | |
| -\(\frac{1}{4}\)x + \(\frac{1}{8}\) | |
| 4\(\frac{2}{3}\)x + 3 | |
| -\(\frac{1}{10}\)x + \(\frac{3}{5}\) |