| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
A right angle measures:
360° |
|
90° |
|
45° |
|
180° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
If a = 1, b = 8, c = 4, and d = 2, what is the perimeter of this quadrilateral?
| 15 | |
| 27 | |
| 24 | |
| 20 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 1 + 8 + 4 + 2
p = 15
The endpoints of this line segment are at (-2, -4) and (2, 4). What is the slope of this line?
| \(\frac{1}{2}\) | |
| 2 | |
| 1\(\frac{1}{2}\) | |
| 1 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -4) and (2, 4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-4.0)}{(2) - (-2)} \) = \( \frac{8}{4} \)Solve for z:
z2 - 3z - 84 = -3z - 3
| -1 or -6 | |
| 3 or -8 | |
| 9 or -9 | |
| 3 or -4 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 - 3z - 84 = -3z - 3
z2 - 3z - 84 + 3 = -3z
z2 - 3z + 3z - 81 = 0
z2 - 81 = 0
Next, factor the quadratic equation:
z2 - 81 = 0
(z - 9)(z + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 9) or (z + 9) must equal zero:
If (z - 9) = 0, z must equal 9
If (z + 9) = 0, z must equal -9
So the solution is that z = 9 or -9
On this circle, line segment CD is the:
diameter |
|
circumference |
|
chord |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).