ASVAB Math Knowledge Practice Test 420278

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4c - 4c = -c + 7y + 8 for c in terms of y.

2\(\frac{1}{5}\)y + 1\(\frac{3}{5}\)
-1\(\frac{2}{3}\)y - \(\frac{1}{3}\)
2\(\frac{4}{5}\)y - 1
1\(\frac{4}{5}\)y + \(\frac{4}{5}\)