ASVAB Math Knowledge Practice Test 424357 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

diameter

circumference

radius


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Solve for b:
-3b - 1 < \( \frac{b}{4} \)

45% Answer Correctly
b < 1\(\frac{4}{11}\)
b < \(\frac{7}{64}\)
b < -\(\frac{4}{13}\)
b < -1\(\frac{17}{37}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-3b - 1 < \( \frac{b}{4} \)
4 x (-3b - 1) < b
(4 x -3b) + (4 x -1) < b
-12b - 4 < b
-12b - 4 - b < 0
-12b - b < 4
-13b < 4
b < \( \frac{4}{-13} \)
b < -\(\frac{4}{13}\)


3

If a = c = 2, b = d = 6, what is the area of this rectangle?

80% Answer Correctly
9
35
42
12

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 2 x 6
a = 12


4

The dimensions of this trapezoid are a = 6, b = 6, c = 8, d = 2, and h = 5. What is the area?

51% Answer Correctly
32\(\frac{1}{2}\)
12
20
18

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 2)(5)
a = ½(8)(5)
a = ½(40) = \( \frac{40}{2} \)
a = 20


5

If side a = 6, side b = 8, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{98} \)
10
\( \sqrt{97} \)
\( \sqrt{80} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 62 + 82
c2 = 36 + 64
c2 = 100
c = \( \sqrt{100} \)
c = 10