ASVAB Math Knowledge Practice Test 424406

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 8a = 2a + 2z - 2 for a in terms of z.

-z + 1\(\frac{2}{7}\)
-3\(\frac{1}{4}\)z - 2
-\(\frac{4}{9}\)z - \(\frac{5}{9}\)
5z - 1