When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 5c = 3c - x + 9 for c in terms of x.
| \(\frac{5}{12}\)x + \(\frac{1}{3}\) | |
| \(\frac{1}{6}\)x + \(\frac{1}{2}\) | |
| -\(\frac{1}{11}\)x - \(\frac{4}{11}\) | |
| -1\(\frac{1}{5}\)x + 1\(\frac{4}{5}\) |