When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 4c = 6c - 3z - 9 for c in terms of z.
| -\(\frac{1}{3}\)z + 1\(\frac{1}{2}\) | |
| -\(\frac{3}{4}\)z - 1\(\frac{3}{4}\) | |
| -4z + 1 | |
| \(\frac{7}{10}\)z + \(\frac{9}{10}\) |