ASVAB Math Knowledge Practice Test 424978

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a - 7a = 7a + 4z - 6 for a in terms of z.

-\(\frac{2}{5}\)z + \(\frac{7}{15}\)
-\(\frac{11}{13}\)z + \(\frac{6}{13}\)
\(\frac{3}{5}\)z - \(\frac{1}{5}\)
5z + 1\(\frac{1}{2}\)