ASVAB Math Knowledge Practice Test 425519

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a + 6a = a - y + 8 for a in terms of y.

1\(\frac{2}{5}\)y - 1\(\frac{3}{5}\)
-\(\frac{13}{14}\)y - \(\frac{5}{14}\)
\(\frac{3}{4}\)y + 2\(\frac{1}{4}\)
2\(\frac{2}{5}\)y - \(\frac{4}{5}\)