ASVAB Math Knowledge Practice Test 426782

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve a - 3a = 9a + z + 1 for a in terms of z.

-2\(\frac{2}{5}\)z - \(\frac{4}{5}\)
\(\frac{3}{8}\)z + \(\frac{3}{4}\)
-\(\frac{1}{2}\)z - \(\frac{1}{8}\)
2z + 3