ASVAB Math Knowledge Practice Test 426898 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

If side a = 2, side b = 7, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{17} \)
\( \sqrt{61} \)
\( \sqrt{106} \)
\( \sqrt{53} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 72
c2 = 4 + 49
c2 = 53
c = \( \sqrt{53} \)


2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

vertical, supplementary

supplementary, vertical

acute, obtuse

obtuse, acute


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


3

Solve for b:
-5b - 9 < \( \frac{b}{6} \)

44% Answer Correctly
b < -\(\frac{25}{26}\)
b < -1\(\frac{23}{31}\)
b < 2\(\frac{10}{11}\)
b < 2\(\frac{8}{11}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-5b - 9 < \( \frac{b}{6} \)
6 x (-5b - 9) < b
(6 x -5b) + (6 x -9) < b
-30b - 54 < b
-30b - 54 - b < 0
-30b - b < 54
-31b < 54
b < \( \frac{54}{-31} \)
b < -1\(\frac{23}{31}\)


4

Simplify 6a x 6b.

86% Answer Correctly
36\( \frac{b}{a} \)
36ab
36a2b2
12ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

6a x 6b = (6 x 6) (a x b) = 36ab


5

If the base of this triangle is 7 and the height is 5, what is the area?

58% Answer Correctly
44
78
39
17\(\frac{1}{2}\)

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 7 x 5 = \( \frac{35}{2} \) = 17\(\frac{1}{2}\)