ASVAB Math Knowledge Practice Test 42791

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b - 4b = -3b + 5y + 8 for b in terms of y.

3\(\frac{1}{2}\)y - 1\(\frac{1}{2}\)
\(\frac{1}{6}\)y + \(\frac{1}{3}\)
-1\(\frac{1}{3}\)y + \(\frac{1}{3}\)
1\(\frac{1}{2}\)y + 1\(\frac{1}{3}\)