ASVAB Math Knowledge Practice Test 428417 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

division

pairs

addition

exponents


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


2

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

intersects

trisects

midpoints

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


3

Solve for z:
z2 + 3z - 15 = -3z + 1

49% Answer Correctly
2 or -1
-2 or -9
2 or -8
9 or -2

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z2 + 3z - 15 = -3z + 1
z2 + 3z - 15 - 1 = -3z
z2 + 3z + 3z - 16 = 0
z2 + 6z - 16 = 0

Next, factor the quadratic equation:

z2 + 6z - 16 = 0
(z - 2)(z + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z + 8) must equal zero:

If (z - 2) = 0, z must equal 2
If (z + 8) = 0, z must equal -8

So the solution is that z = 2 or -8


4

If a = 8, b = 6, c = 4, and d = 7, what is the perimeter of this quadrilateral?

88% Answer Correctly
25
20
16
27

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 8 + 6 + 4 + 7
p = 25


5

The dimensions of this cube are height (h) = 5, length (l) = 2, and width (w) = 2. What is the surface area?

51% Answer Correctly
48
168
236
100

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 2 x 2) + (2 x 2 x 5) + (2 x 2 x 5)
sa = (8) + (20) + (20)
sa = 48