ASVAB Math Knowledge Practice Test 42861

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b + b = 8b - 6z - 3 for b in terms of z.

-z - 5
-3z - 2\(\frac{1}{3}\)
1\(\frac{2}{5}\)z + \(\frac{3}{5}\)
-2\(\frac{1}{5}\)z - \(\frac{4}{5}\)