| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.62 |
| Score | 0% | 72% |
The endpoints of this line segment are at (-2, -5) and (2, 5). What is the slope-intercept equation for this line?
| y = -\(\frac{1}{2}\)x - 4 | |
| y = x - 4 | |
| y = -2x - 4 | |
| y = 2\(\frac{1}{2}\)x + 0 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -5) and (2, 5) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(5.0) - (-5.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)Plugging these values into the slope-intercept equation:
y = 2\(\frac{1}{2}\)x + 0
What is the area of a circle with a radius of 5?
| 5π | |
| 16π | |
| 25π | |
| 4π |
The formula for area is πr2:
a = πr2
a = π(52)
a = 25π
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
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deconstructing |
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factoring |
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normalizing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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pairs |
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addition |
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exponents |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
If a = 2, b = 7, c = 5, and d = 6, what is the perimeter of this quadrilateral?
| 20 | |
| 16 | |
| 28 | |
| 18 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 2 + 7 + 5 + 6
p = 20