ASVAB Math Knowledge Practice Test 43055

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a - 6a = -2a + 4z - 8 for a in terms of z.

2\(\frac{1}{2}\)z - 2
\(\frac{1}{7}\)z - \(\frac{6}{7}\)
3\(\frac{1}{2}\)z - 4\(\frac{1}{2}\)
1\(\frac{1}{6}\)z + \(\frac{1}{6}\)