ASVAB Math Knowledge Practice Test 431321

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9c + 6c = c - 5y - 2 for c in terms of y.

4y + 6
-y - \(\frac{1}{6}\)
y + \(\frac{1}{4}\)
1\(\frac{1}{10}\)y + \(\frac{1}{5}\)