ASVAB Math Knowledge Practice Test 432260 Results

Your Results Global Average
Questions 5 5
Correct 0 2.61
Score 0% 52%

Review

1

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

expression

problem

equation


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


2

The dimensions of this trapezoid are a = 6, b = 6, c = 9, d = 2, and h = 4. What is the area?

51% Answer Correctly
16
13\(\frac{1}{2}\)
27\(\frac{1}{2}\)
10

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 2)(4)
a = ½(8)(4)
a = ½(32) = \( \frac{32}{2} \)
a = 16


3

Solve for a:
3a - 7 > \( \frac{a}{-1} \)

44% Answer Correctly
a > \(\frac{3}{4}\)
a > \(\frac{1}{4}\)
a > -\(\frac{9}{82}\)
a > 1\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

3a - 7 > \( \frac{a}{-1} \)
-1 x (3a - 7) > a
(-1 x 3a) + (-1 x -7) > a
-3a + 7 > a
-3a + 7 - a > 0
-3a - a > -7
-4a > -7
a > \( \frac{-7}{-4} \)
a > 1\(\frac{3}{4}\)


4

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π r

c = π d2

c = π d

c = π r2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


5

Simplify (7a)(4ab) + (4a2)(3b).

65% Answer Correctly
40a2b
77a2b
-16ab2
40ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(7a)(4ab) + (4a2)(3b)
(7 x 4)(a x a x b) + (4 x 3)(a2 x b)
(28)(a1+1 x b) + (12)(a2b)
28a2b + 12a2b
40a2b