| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
Solve for a:
2a + 2 > \( \frac{a}{7} \)
| a > \(\frac{4}{7}\) | |
| a > -\(\frac{9}{62}\) | |
| a > -1\(\frac{1}{13}\) | |
| a > -3\(\frac{3}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
2a + 2 > \( \frac{a}{7} \)
7 x (2a + 2) > a
(7 x 2a) + (7 x 2) > a
14a + 14 > a
14a + 14 - a > 0
14a - a > -14
13a > -14
a > \( \frac{-14}{13} \)
a > -1\(\frac{1}{13}\)
A trapezoid is a quadrilateral with one set of __________ sides.
right angle |
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equal angle |
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parallel |
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equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
Solve for y:
y2 + 6y + 16 = -2y + 1
| -3 or -8 | |
| -3 or -5 | |
| 4 or 1 | |
| 3 or -7 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + 6y + 16 = -2y + 1
y2 + 6y + 16 - 1 = -2y
y2 + 6y + 2y + 15 = 0
y2 + 8y + 15 = 0
Next, factor the quadratic equation:
y2 + 8y + 15 = 0
(y + 3)(y + 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 3) or (y + 5) must equal zero:
If (y + 3) = 0, y must equal -3
If (y + 5) = 0, y must equal -5
So the solution is that y = -3 or -5
Which of the following is not required to define the slope-intercept equation for a line?
x-intercept |
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y-intercept |
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\({\Delta y \over \Delta x}\) |
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slope |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
The formula for the area of a circle is which of the following?
a = π r2 |
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a = π d2 |
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a = π d |
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a = π r |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.