To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s²

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c² = a² + b²
c² = 2² + 2²
c² = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-7a - 7 < -1 + 3a
-7a < -1 + 3a + 7
-7a - 3a < -1 + 7
-10a < 6
a < \( \frac{6}{-10} \)
a < -\(\frac{3}{5}\)

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

6c + 7z = 5c + 3z - 6
6c = 5c + 3z - 6 - 7z
6c - 5c = 3z - 6 - 7z
c = -4z - 6

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 9 x 6
a = 54