When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 4c = 4c - 2y - 2 for c in terms of y.
| 8y + 3 | |
| 6\(\frac{1}{2}\)y + 1 | |
| -2y - 4\(\frac{1}{2}\) | |
| \(\frac{3}{4}\)y + \(\frac{1}{4}\) |