| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
A right angle measures:
90° |
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180° |
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45° |
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360° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
Order the following types of angle from least number of degrees to most number of degrees.
right, acute, obtuse |
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acute, obtuse, right |
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right, obtuse, acute |
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acute, right, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
The dimensions of this trapezoid are a = 5, b = 8, c = 6, d = 6, and h = 3. What is the area?
| 9 | |
| 24 | |
| 21 | |
| 19\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(8 + 6)(3)
a = ½(14)(3)
a = ½(42) = \( \frac{42}{2} \)
a = 21
Which of the following statements about parallel lines with a transversal is not correct?
all of the angles formed by a transversal are called interior angles |
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same-side interior angles are complementary and equal each other |
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all acute angles equal each other |
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angles in the same position on different parallel lines are called corresponding angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Find the value of c:
6c + z = 6
5c - 5z = 6
| 1\(\frac{13}{42}\) | |
| -\(\frac{3}{4}\) | |
| \(\frac{67}{68}\) | |
| 1\(\frac{1}{35}\) |
You need to find the value of c so solve the first equation in terms of z:
6c + z = 6
z = 6 - 6c
then substitute the result (6 - 6c) into the second equation:
5c - 5(6 - 6c) = 6
5c + (-5 x 6) + (-5 x -6c) = 6
5c - 30 + 30c = 6
5c + 30c = 6 + 30
35c = 36
c = \( \frac{36}{35} \)
c = 1\(\frac{1}{35}\)