ASVAB Math Knowledge Practice Test 43505

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7a + 6a = -7a - 3z + 9 for a in terms of z.

-\(\frac{1}{9}\)z - \(\frac{1}{9}\)
7z + 1
-\(\frac{9}{14}\)z + \(\frac{9}{14}\)
\(\frac{5}{12}\)z + \(\frac{1}{6}\)