ASVAB Math Knowledge Practice Test 435815

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6a + 7a = 3a + 4z - 2 for a in terms of z.

\(\frac{3}{13}\)z - \(\frac{8}{13}\)
-z - \(\frac{2}{3}\)
5z + 4
1\(\frac{1}{9}\)z - 1