ASVAB Math Knowledge Practice Test 436307

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a - 3a = -8a - 2z + 2 for a in terms of z.

7z + 1\(\frac{1}{2}\)
-\(\frac{2}{5}\)z - \(\frac{2}{15}\)
\(\frac{1}{2}\)z + 1
-\(\frac{1}{8}\)z + \(\frac{1}{2}\)