| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.32 |
| Score | 0% | 46% |
If a = c = 3, b = d = 1, what is the area of this rectangle?
| 3 | |
| 9 | |
| 14 | |
| 8 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 3 x 1
a = 3
If the base of this triangle is 4 and the height is 7, what is the area?
| 78 | |
| 14 | |
| 67\(\frac{1}{2}\) | |
| 66 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 4 x 7 = \( \frac{28}{2} \) = 14
The formula for the area of a circle is which of the following?
c = π r |
|
c = π d2 |
|
c = π d |
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c = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Which of the following statements about parallel lines with a transversal is not correct?
all acute angles equal each other |
|
angles in the same position on different parallel lines are called corresponding angles |
|
all of the angles formed by a transversal are called interior angles |
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same-side interior angles are complementary and equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Solve -9c - 7c = 3c + 3z + 1 for c in terms of z.
| -9z + 8 | |
| 2z + 6 | |
| -2\(\frac{3}{5}\)z - \(\frac{2}{5}\) | |
| -\(\frac{5}{6}\)z - \(\frac{1}{12}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-9c - 7z = 3c + 3z + 1
-9c = 3c + 3z + 1 + 7z
-9c - 3c = 3z + 1 + 7z
-12c = 10z + 1
c = \( \frac{10z + 1}{-12} \)
c = \( \frac{10z}{-12} \) + \( \frac{1}{-12} \)
c = -\(\frac{5}{6}\)z - \(\frac{1}{12}\)