ASVAB Math Knowledge Practice Test 437617 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

On this circle, line segment AB is the:

70% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

equation

expression

problem


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


3

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

radius

chord

diameter

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Simplify (4a)(3ab) - (4a2)(3b).

59% Answer Correctly
0a2b
49ab2
24ab2
2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(3ab) - (4a2)(3b)
(4 x 3)(a x a x b) - (4 x 3)(a2 x b)
(12)(a1+1 x b) - (12)(a2b)
12a2b - 12a2b
0a2b


5

What is 7a6 + 8a6?

74% Answer Correctly
15a12
15
15a6
56a12

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a6 + 8a6 = 15a6