ASVAB Math Knowledge Practice Test 438487

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2c + 8c = c - 4z - 2 for c in terms of z.

z - 3
-3\(\frac{1}{2}\)z - 1
z - 4\(\frac{1}{2}\)
4z + \(\frac{2}{3}\)