When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 7c = -3c + 2z + 5 for c in terms of z.
| -\(\frac{7}{12}\)z + \(\frac{1}{3}\) | |
| -\(\frac{5}{6}\)z + \(\frac{5}{6}\) | |
| -\(\frac{13}{15}\)z - \(\frac{3}{5}\) | |
| \(\frac{2}{3}\)z - \(\frac{1}{3}\) |