ASVAB Math Knowledge Practice Test 438871

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c - c = 4c - 3z + 6 for c in terms of z.

\(\frac{2}{3}\)z - 2
2z + \(\frac{3}{4}\)
\(\frac{1}{2}\)z - \(\frac{3}{4}\)
-3z - 3