When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 5c = -3c + 6y - 2 for c in terms of y.
| \(\frac{1}{5}\)y - \(\frac{1}{5}\) | |
| -\(\frac{5}{13}\)y - \(\frac{4}{13}\) | |
| 1\(\frac{1}{2}\)y - 1 | |
| y - \(\frac{2}{11}\) |