When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 3c = c + 4y - 3 for c in terms of y.
| \(\frac{4}{5}\)y - \(\frac{2}{5}\) | |
| \(\frac{1}{8}\)y - \(\frac{3}{8}\) | |
| -2\(\frac{3}{5}\)y - 1 | |
| 15y - 4 |