ASVAB Math Knowledge Practice Test 443732

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6b + 4b = -9b + y - 5 for b in terms of y.

-\(\frac{3}{5}\)y + \(\frac{1}{2}\)
-\(\frac{1}{5}\)y - \(\frac{1}{3}\)
-\(\frac{1}{2}\)y + \(\frac{1}{4}\)
3y + 2\(\frac{2}{3}\)