ASVAB Math Knowledge Practice Test 444242

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5b + 4b = b + 5x - 6 for b in terms of x.

1\(\frac{1}{2}\)x - \(\frac{1}{4}\)
-\(\frac{1}{2}\)x + 3\(\frac{1}{2}\)
\(\frac{1}{4}\)x - 1\(\frac{1}{2}\)
-\(\frac{16}{17}\)x + \(\frac{7}{17}\)